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defon
2 years ago
13

The length of a rectangle is three times its width. If the area of the rectangle is 243 m squared, find it’s perimeter

Mathematics
1 answer:
vlabodo [156]2 years ago
3 0

Answer: 72

Step-by-step explanation:

L= 3W

area of a rectangle  A= LxW

replace L with 3 W

A=3W*W= 3w^2

243=3W^2

243/3=W^2

81=w^2, and W=9

L=3*9=27

P= (L+W)=2(27+9)=72

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Answer:

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Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

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<u>Proof </u><u>:</u><u>-</u><u> </u>

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Take out 2 common from the numerator ,

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Simplify ,

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Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

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