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2 years ago

The length of a rectangle is three times its width. If the area of the rectangle is 243 m squared, find it’s perimeter

Mathematics

1 answer:

vlabodo [156]2 years ago

3 0

Answer: 72

Step-by-step explanation:

L= 3W

area of a rectangle A= LxW

replace L with 3 W

A=3W*W= 3w^2

243=3W^2

243/3=W^2

81=w^2, and W=9

L=3*9=27

P= (L+W)=2(27+9)=72

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sergeinik [125]

First we need to find where the 2 graphs intercept.

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6 0

2 years ago

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Fantom [35]

Answer:

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Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

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[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

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Use $(a-b)^2=a^2+b^2-2ab$

So,

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7 0

2 years ago

The diagram shows a circle with center C, a diameter RS, and an inscribed triangle RST.

snow_tiger [21]

Answer:

x = 26

Step-by-step explanation:

m<RTS = 4x - 14 (given)

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4x - 14 = 90

4x - 14 + 14 = 90 + 14 (addition property of equality)

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6 0

2 years ago

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Bumek [7]

Answer

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Step-by-step explanation:

needed points

4 0

2 years ago

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aev [14]

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Step-by-step explanation:

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1 year ago