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STatiana [176]
3 years ago
9

What are the solutions to the equation (2x-5)(3x-1)=0?

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0
(2x-5)(3x-1)=0

2x-5 = 0      or   3x-1= 0
2x = 5               3x = 1
x = 5/2              x = 1/3

Answer: x=5/2; x=1/3


artcher [175]3 years ago
6 0

The answer is C. x = \frac{5}{2} 0r x = \frac{1}{3}

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IF J is between C and T, find the value of x and JT. CJ=8x+5, CT=55, and JT=4x+2
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Answer:

<h2>x = 4</h2><h2>JT = 18</h2>

Step-by-step explanation:

Given three points J, C and T on a line, if J is between C and T then;

CJ + JT = CT.

Given CJ=8x+5, CT=55, and JT=4x+2, substituting this parameters in the equation above will give;

(8x+5)+(4x+2)= 55\\8x+4x+5+2 = 55\\12x+7 = 55\\12x = 55-7\\12x = 48\\ x = \frac{48}{12} \\x = 4

SInce JT = 4x+2

JT = 4(4)+2\\JT = 16+2\\JT = 18

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