What are the solutions to the equation (2x-5)(3x-1)=0?

Mathematics

2 answers:

lutik1710 [3]3 years ago

6 0

(2x-5)(3x-1)=0

2x-5 = 0 or 3x-1= 0
2x = 5 3x = 1
x = 5/2 x = 1/3

Answer: x=5/2; x=1/3

artcher [175]3 years ago

6 0

The answer is C. x = $\frac{5}{2}$ 0r x = $\frac{1}{3}$

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For each of the three events, there are 8 possible outcomes, so the probability of each event is,

$P(event)=\frac{favorable\text{ }outcomes}{possible\text{ }outcomes}=\frac{favorable\text{ }outcomes}{8}$

• Event A:, there must be only odd numbers in the last two rolls, which are either ,EOO or OOO,. This event has 2 favorable outcomes, ,so its probability is 1/4,.

• Event B,: this is the complementary event to event A. Here the last two rolls must be even numbers - both or only one of the last two: ,OOE, EEO, EOE, OEE, EEE, OEO,. This event has 6 favorable outcomes, so ,its probability is 3/4,.

• Event C,: this event is when the first and last rolls are even numbers in the same event. This is either ,EOE or EEE,. Since this event has 2 favorable outcomes, ,its probability is 1/4,.