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Tems11 [23]
2 years ago
6

Esther is constructing a table of values that satisfies the definition of a function f(x).

Mathematics
2 answers:
yawa3891 [41]2 years ago
6 0
I think is B because is the one that i think
Katyanochek1 [597]2 years ago
4 0
B. -12 I’m not 100% sure but I think it’s B
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To evaluate each expressi<br>- 2. (6+4)(-12) =​
NeX [460]

Answer:

Step-by-step explanation:

(6 + 4)(-12) =

10 * -12 =

-120 <==

4 0
3 years ago
What is the solution to 0.4(12 - 3x) = 0.3(12x - 16)?<br> F. 4<br> G. 2<br> H. -2<br> J. -4
jolli1 [7]
Answer : H-2
I can sure that's the answer
6 0
3 years ago
PLEASE HELP ASAP
Elena L [17]
36.08 = 8.8t

The distance is a positive because it shows the total distance traveled

36.08 = 8.8t
4.1=t
3 0
4 years ago
Ricardo has 2 cases of video games Edith the same number of games in each case. He gives 4 games to his brother. Ricardo has 10
alisha [4.7K]

Answer:

7 games

Step-by-step explanation:

Ricardo has 2 cases with x number of games in each. This means 2x is the amount of video games in both. He gives away 4. He now has 2x-4 and has 10 left. This is 2x-4=10. Solve for x.

2x - 4 = 10

2x = 14

x=7

7 0
3 years ago
Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}

Take the square in both sides of this equation to get

(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2

(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0

You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

4 0
4 years ago
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