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raketka [301]
3 years ago
5

4. Find the length of Y Find the missing angle marked "e" 11.3 129% 5.91

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

b 129%

Step-by-step explanation:

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What percent of $150 is $87
vesna_86 [32]
87/150=0.58
0.58*100=58

$87 is 58% of $150

Good luck!
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3 years ago
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I need help thank you
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C.
you just have to count 4 spaces to the left and 3 down for each point
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EASY- 50 PTS<br> ALGEBRA/ FUNCTION/ GRAPH MATH
alekssr [168]

9514 1404 393

Answer:

  B.  Up 1 and 2 to the left

Step-by-step explanation:

The second graph (blue) is up 1 and 2 left of the first graph (red).

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You can compare the given equations to the form ...

  y = a(x -h)^2 +k

For the first graph, we have (h, k) = (6, -1).

For the second graph, we have (h, k) = (4, 0).

Then the amount added to the first to make the second is ..

  (4, 0) -(6, -1) = (-2, 1) . . . . . . a translation 2 left and 1 up

3 0
3 years ago
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At the same store, Peter bought 2 pairs of pants and 5 shirts for $61, and Jessica bought 3 pairs of pants and 4 shirts for $67.
svetlana [45]

Hey there!!

Given :

The total cost for 2 pairs of pants and 5 shirts is $61.

The total cost for 3 pairs of paints and 4 shirts is $67.

<em>Let's take the cost for each pair of paints as 'p' and the cost for each shirt as 's'. </em>

Now, let's get these into an equation.

<em>Peter's equation</em> :

... 2p + 5s = 61

<em>Jessica's equation : </em>

...3p + 4s = 67

......................................................................................................

2p + 5s = 61 --- (1)

3p + 4s = 67 --- (2)

Multiply the first equation with 3 and the second equation with 2.

6p + 15s = 183

6p + 8s = 134

S<em>ubtract both the equations - </em>

... 7s = 49

Divide both sides with 7.

... s = 7

<u><em>Hence, the cost of each shirt is $7. </em></u>

Hope my answer helps!!


6 0
3 years ago
Please help..click on picture...I rrally need help
Alekssandra [29.7K]
So the students are on 5:6 ratio from volleyball to football, and we know there are 220 students in total.

\bf \cfrac{volleyball}{football}\qquad 5:6\qquad \cfrac{5}{6}\implies \cfrac{5\cdot \frac{220}{5+6}}{6\cdot \frac{220}{5+6}}\implies \cfrac{5\cdot 20}{6\cdot 20}\implies \cfrac{100}{\stackrel{football}{120}}
8 0
3 years ago
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