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3 years ago

14

Can someone please explain this to me? Thank you so much! (#18, H.O.T problems)

1 answer:

andreev551 [17]3 years ago

8 0

Also you do not look like your in first grade o-o

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HELP PLEASE , ASAP ; 100 POINTS

LUCKY_DIMON [66]

Answer:

icoles

Step-by-step explanation:

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3 years ago

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90 men and 60 women were asked if they had watched the latest 'Expendables' movie.

Stolb23 [73]

Answer:

63 men said no.

Step-by-step explanation

3/5 * 2/2 = 6/10, 6/10 - 3/10 (women) = 3/10 meaning 7/10 men said no. 90*1.7 = 153, 153-90=63

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3 years ago

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The triangles are similar. Find the value of x.

LUCKY_DIMON [66]

Answer: 95

Step-by-step explanation:

I am in geometry this year. We know by the AA thorem that all three angles are similar. Since both triangles have sides 45 and 40. We know that the last side has to 95.

Hope this helps :)

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3 years ago

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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Plz help with these first one gets brainliest

vlabodo [156]

Answer:

A=(1,6) B=(1,6)

Step-by-step explanation:

Its the absolotle value between them.

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2 years ago

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