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juin [17]
3 years ago
9

Fractorise the following (a-b)²+(a-b)​

Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Step-by-step explanation:

taking common (a-b)

so we get the answer

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I'm trying to find 1, 2, & 3 but idk how? Sry if it's sideways I'm new ​
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

m∠1+∠2=180

2x+40+2y+40=180

2x+2y=180-80

2x+2y=100

x+y=50

x=50-y

m∠1=m∠3

2x+40=x+2y

2x-x=2y-40

x=2y-40

2y-40=50-y

2y+y=50+40

3y=90

y=30

x=50-y=50-30=20

m∠1=2x+40=2×20+40=80°

m∠2=2y+40=2×30+40=60+40=100°

m∠3=x+2y=20+2×30=80°

6 0
3 years ago
How is a relationship determined when looking at a scatterplot?
snow_tiger [21]

Answer:

The relationship between two variables is called their correlation The relationship between two variables is called their correlation

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Solve the quadratic equation for x.What is one of the roots?
zubka84 [21]

-13 because 6 x 2 = 12 plus x = -13 x represents 1 btw
7 0
3 years ago
Read 2 more answers
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
What is the equation of this line in standard form
Yuri [45]

Line joining (-3, -1) and (1/2, 2)

Point point form for a line is

(c-a)(y-b) = (d-b)(x-a)

(1/2 - - 3)(y - -1) = (2 - -1)(x - -3)

(7/2)(y+1)=3(x+3)

7(y+1)=6(x+3)

7 - 6(3) = 6x - 7y

6x - 7y = -11

Answer: second choice, 6x - 7y = -11

3 0
3 years ago
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