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2 years ago

List and describe four services that comprise IT infrastructure, beyond physical devices and software applications.

Computers and Technology

1 answer:

masha68 [24]2 years ago

6 0

The four services that comprise IT infrastructure are:

Telecommunications services.
Data management services .
Application software services.
Physical facilities management services.

<h3>What does these services do?</h3>

Telecommunications services is known to help in terms of giving data, voice, and video network.

Data management services helps to save , manage, and analyze all data. Application software services helps to give firms-wide range capabilities.

The Physical facilities management services helps to make and handle physical installations of technology.

Therefore, The four services that comprise IT infrastructure are:

Telecommunications services.
Data management services .
Application software services.
Physical facilities management services.

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2 years ago

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3 years ago

Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo

dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){

int lenstr1=0;

while(str1[lenstr1] != '\0'){ lenstr1++; }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

while (str2[index] != '\0'){

if (str1[i] == str2[index]){

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break; }

else{ retIndex=0; }

index++; }

if (retIndex == 0){ return i; }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){ lenstr1++; }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

while (str2[index] != '\0'){

If current element of str2 and str1 are the same

if (str1[i] == str2[index]){

Set the returned index to 1

retIndex=1;

Then exit the loop

break; }

If otherwise, set the returned index to 0

else{ retIndex=0; }

Increase index by 1

index++; }

This returns the calculated returned index; if no matching is found, it returns -1

if (retIndex == 0){ return i; }else{return -1;}}

}

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3 years ago