Answer:
hope this helps .keep on learning
The standard form is:

Degree = 5, leading coefficient=4
The 5th degree polynomial is:
Quintic function
it is a trinomial
<u>What is standard form of a polynomial?</u>
When expressing a polynomial in its standard form, the greatest degree of terms are written first, followed by the next degree, and so on.
So, standard form is:

To find the degree of the polynomial, add up the exponents of each term and select the highest sum ( if there are more than 1 variable in single term) or highest power of variable
Degree = 5
In a polynomial, the leading term is the term with the highest power of x.
So, leading coefficient=4
The 5th degree polynomial is:
Quintic function
It has 3 terms. so, it is a trinomial
To learn more about the standard form of a polynomial from the given link
brainly.com/question/26552651
#SPJ1
Since
, we can rewrite the integral as

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

Both integrals are quite immediate: you only need to use the power rule

to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
Hi there!

The greatest common factor of 40 and 24 is 8.
8 goes into 40 5 times:
8 goes into 24 3 times.
We can rewrite this expression for distribution using the amount of times 8 goes into both numbers:
8(5 + 3)
Using this, we get:
8(5) + 8(3) = 40 + 24.
Answer:
Step-by-step explanation:
You do not need to where the formula comes from but, just for fun, here’s a hint
To add up the numbers 1 to 10
Write out the numbers
1 2 3 4 5 6 7 8 9 10
Write them backwards
10 9 8 7 6 5 4 3 2 1
Add up both lists
11 11 11 11 11 11 11 11 11 11
This is 10 × 11 = 110
But this is twice the sum as two lots were added together
So the sum of the numbers 1 to 10 is 110 ÷ 2 = 55
ArSeqSum Notes fig4, downloadable IGCSE & GCSE Maths revision notes