Question

+ 3x - 9x^{2}=-16" align="absmiddle" class="latex-formula">

Answer 1

The solution of x in -6 + 3x - 9x^2 = -16 is $x = \frac{3 \pm \sqrt{369}}{18}$

How to solve the equation?

The equation is given as:

-6 + 3x - 9x^2 = -16

Add 16 to both sides

10 + 3x - 9x^2 = 0

Rewrite as:

9x^2 - 3x - 10 = 0

Solve for x using the quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

So, we have:

$x = \frac{3 \pm \sqrt{(-3)^2 - 4 * 9 * -10}}{2 * 9}$

Evaluate

$x = \frac{3 \pm \sqrt{369}}{18}$

Hence, the solution of x in -6 + 3x - 9x^2 = -16 is $x = \frac{3 \pm \sqrt{369}}{18}$

Read more about quadratic functions at:

brainly.com/question/1497716

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