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KonstantinChe [14]
2 years ago
12

What is the probability that the spinner lands on an even number or on the unshaded section? one-fifth two-fifths three-fifths f

our-fifths
Mathematics
1 answer:
Tasya [4]2 years ago
5 0

The probability that the spinner lands on an even number or on the unshaded section is; 3/5

<h3>How to find the probability?</h3>

From the spinner attached, we see that the number of sections on the spinner is 5 sections.

Now, we can also see that;

Number of even numbers section = 2

Number of shaded sections = 1

Thus, probability that the spinner lands on an even number or on the unshaded section is;

P(even number or unshaded section) = (2 + 1)/5 = 3/5

Read more about Probability at; brainly.com/question/24756209

#SPJ1

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a_n=48+3(2n-1)

The formula of the sum of the arithmetic sequence:
S_n=\dfrac{a_1+a__n}{2}\cdot n
calculate:
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substitute
S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n
Your answer is:
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