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Vadim26 [7]
3 years ago
15

A line passes through the points (0, -8) and (5, 10). What is its equation in slope-intercep

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0
<h2>Answer:    y = ¹⁸/₅ x  - 8 </h2>

Step-by-step explanation:

         For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:

        The question gives us two points, (0, -8) and (5, 10), from which we can find the slope and later the equation of the line.

<u>Finding the Slope</u>  

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                          =  (10 - (- 8)) ÷ (5 - 0)

                                          =   ¹⁸/₅  

<u>Finding the Equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

                                  ⇒  y - (-8) =  ¹⁸/₅ (x - 0)

   we could also transform this into the slope-intercept form ( y = mx + c)

                                    since  y - (-8) =  ¹⁸/₅ (x - 0)

                                          ⇒     y + 8 =  ¹⁸/₅ x

                                                 

                                                 ∴  y = ¹⁸/₅ x  - 8

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

<em />

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Step 1

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The revenue is given by the function;

\begin{gathered} f(p)=150p-5p^2 \\ f(p)\text{ is the revenue and should be equal to 0 according to the question.} \\ p=\text{ The price of tickets for the day for the revenue to be 0} \end{gathered}

To solve this problem or to find this price at which tickets will be solved to give us zero revenue, we must equate the given function for the revenue to 0 and find the value of p, the price of the tickets that make the function to be equal to 0.

For the theatre to make $0 in revenue, this means f(p)=0.

Therefore, we will equate f(p) to 0

Step 2

Equate f(p) to 0

\begin{gathered} 0=150p-5p^2 \\ p(150-5p)=0----(\text{factorize)} \\ p=0 \\ 0r \\ 150-5p=0 \\ 150=5p \\ \frac{5p}{5}=\frac{150}{5} \\ p=30 \\ p=0\text{ or 30} \end{gathered}

Therefore the revenue to be zero, the price of the ticket will be $0 or $30 but the question asked us how high the ticket price will be to get a revenue of 0. Both 0 and 30 gave us revenue of 0 but $30 is higher therefore, the answer will be $30.

Check;

\begin{gathered} 150p-p^2=0 \\ \text{If the price of tickets=0} \\ 150(0)-5(0^2)=0 \\ \text{If p=30} \\ 150(30)-5(30^2)=4500-4500=0 \end{gathered}

Both give us 0 revenue but $30 is higher and the right answer.

Step 3

The equation you can write for revenue of $700 is;

\begin{gathered} 700=150p-5p^2 \\ 5p^2-150p+700=0_{} \end{gathered}

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Step-by-step explanation:

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Which graph can be used to find the solution(s) to 4x=-4x?
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<h2>Answer:</h2>

The graph is shown in the Figure below

<h2>Step-by-step explanation:</h2>

In this exercise, we have an equation. On the left side we have a straight line with slope m=4 and there is no any y-intercept. On the right side, on the other had, we also have a straight line, but the slope here is  m=-4. Therefore, by plotting these two straight lines, we have that the solution is the origin, that is, the point (0, 0).


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Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) Z=2.45

b) P Value=0.0073

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach P=21.4=>0.214

Population Size N=498

Sample size n=12

Therefore

P'=\frac{129}{498}

P'=0.2590

Generally the Null and Alternative Hypothesis is mathematically given by

H_0:P=0.214

H_a:=P>0.214

Test Statistics

Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}

Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}

Z=2.45

Therefore P Value is given as

P Value =P(Z\geq 2.45)

P Value =1-P(Z\leq 2.45)

P Value =1-0.99268525

P Value=0.0073

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