That's not a linear system, but you have an awesome school system for giving you this problem.
Multiply by 6xy to clear the fractions.
That's a second degree equation, also known as a conic. That one happens to be a hyperbola.
Let's clear the fractions from the second equation, multiplying out common denominator xy:
We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,
We have to rule out x=0 because it's in the denominator.
Answer: (44/19, 33/20)
The four transformations:
Translation, Rotation, Reflection, and Scaling
Each of these transformations change how or where the shape is. Each of these transformations change the shape or shapes in different ways. Dilations change the size and sometimes even the shape of the shape; translation, rotation, and reflection just move the shape around they don't change the size or shape of it.
Is that what you are looking for? Let me know if there anything more...
Answer:
The answer is choice 2 and 3, that is "The quotient has a final decimal and the whole number is less than 11".
Step-by-step explanation:
The product of a ratio: amount (r) over other(s) (variance from 0) becomes mandatory to note this quotient and in the following case Thus q is = 0.0882352941.
It wasn't a repeating decimal, however a final decimal, so it's got an end.
Its quotient may be less than 11 in total.
Numbers of W = {0,1,2, ...} and 0 < 11 are provided for this entire series of data therefore It's real .
That would be written as:
And the step-by-step equation would be:
→ we take the 2 to the right side of the equation and do the IO*
→we solve for 
→ final answer
*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)
Hope it helped,
BioTeacher101
The answer is B
I know this because 8 divided by -4 =-2
Therefore the answer is: B
