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Makovka662 [10]
2 years ago
15

Solvex + 3 = −6.

Mathematics
1 answer:
Blizzard [7]2 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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Work out <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\frac{1}{5}" align="
NNADVOKAT [17]

Answer:

Here we will explain how to calculate one half of 80.

One half of 80 is simply one half times 80, which can be written as follows:

One/half x 80

Furthermore, you can convert "one" to "1" and "half" to "2" and then the equation and answer is:

1/2 x 80 = 40.00

Step-by-step explanation:

7 0
2 years ago
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please, i need help like now!! Does anyone know what the mean absolute deviation means and how to solve it. i already searched i
Alona [7]
<span> the mean absolute deviation is the average absolute deviation from the mean and is a common measure of forecast error in time series analysis. </span>
8 0
4 years ago
Anyone know this?????
uranmaximum [27]
Answer: x=13
Explanation:

step 1 - multiply both sides by 6 to get rid of it
step 2 - simplify both sides
step 3 - subtract 1.4 from both sides
x = 13
3 0
3 years ago
Read 2 more answers
Find the volume of the right triangular prism
melisa1 [442]

Answer:

7161 km³

Step-by-step explanation:

28²+b²=32.5²

784+b²=1056.25

b²=1056.25-784

b²=272.25

b=√272.25

b=16.5

1/2x28x16.5x31=7161

4 0
3 years ago
What is the value of y? PLEASE EXPLAIN<br> 8.5 = y/3 &lt;------ Fraction
NISA [10]

Answer:

y=25.5

Step-by-step explanation:

To find y, you need to get it by itself. Ask yourself, what is being done to y, then to undo that, do the opposite. For example, if 3 was added to y, you would need to subtract 3 to cancel out the 3. In this case, what is being done to y? It's being divided by 3. So, you multiply by 3 to cancel that out. Whatever you do to one side of an equation, you also have to do to the other. So,

8.5=\frac{y}{3}   Multiply both sides by 3

3(8.5) = 3(\frac{y}{3})  multiply on the left side, and on the right side the 3s cancel out

25.5=y

5 0
3 years ago
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