Answer:
perimeter of the figure = 37 ft
Step-by-step explanation:
r = 1/2 × (12 - 3 - 3)
r = 1/2 × 6
r = 3 ft
circumference = 2 π r
circumference = 2 × 3.14 × 3
circumference = 18.84
perimeter of the figure = 3 + 3 + 3 + 3 + 3 + 3 + 18.84
perimeter of the figure = 36.84
perimeter of the figure = 37 ft
Answer:
The weight of square is 8 grams.
Step-by-step explanation:
Given that,
The weight of the circle = 2 grams
The weight of the triangle = 4 grams
We need to find the weight of the square. Let the weight of each square is w.
On LHS, 2 circles and 4 squares are there.
On RHS, 2 squares, 4 triangles and 2 circles are there.
For a balanced position,
Weight on LHS = Weight on RHS
2(2)+4(w) = 2(w) + 4(4) +2(2)
4 + 4w = 2w +16 +4
4w-2w = 20-4
2w = 16
w = 8
So, weight of square is 8 grams.
I'm grade 6 I don't know ................
Answer:
-4x^3 + 7y^3 + 5
Step-by-step explanation:
7y^3 - 7x^3 + 4 - 5 + 6 - 3x^3 + 6x^3 Given
7y^3 - 7x^3 - 3x^3 + 6x^3 + 4 - 5 + 6 Rearrange
7y^3 - 4x^3 + 5 Combine the like terms
or
-4x^3 + 7y^3 + 5 Answer
Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=