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3 years ago

Help thx also this for brainliest

Mathematics

2 answers:

fenix001 [56]3 years ago

8 0

Answer:

7. B

8. D

9. A

Step-by-step explanation:

hope this help ls you and also GOOOOOOOOOOOOOOOOO from unspeakable

vova2212 [387]3 years ago

3 0

Answer:

1)b 2)d 3)c

Explination: a bus is 12 meters so you will measure by meters

inches are bigger than centmeters and a nail is almost 2 inches so u will mesaure by inches

a new born baby is most likely to be 9 pounds so u weights by pounds

-mr harris

(ps: brainlist appreciated)

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The scale factor of the blueprint of a wall to the actual wall is 0.07. The area of the actual wall is 36ft² what is the area of

ss7ja [257]

Answer:

The area of the wall on the blueprint is 0.1764 ft²

Step-by-step explanation:

The scale is the relationship that exists between the magnitudes of a drawing and the actual dimensions.

The scale factor is the ratio of the dimensions in two similar figures. The term "similar figures" refers to figures that have the same shape but different sizes.

The ratio between areas is equal to the squared scale factor. This is, the scale factor for areas is the squared scale factor,

To solve scale problems in this case, then the following proportion must be proposed:

$\frac{representation area}{actual area} =scale factor^{2}$

Being:

representation area=?
actual area=36 ft²
scale factor=0.07

Replacing:

$\frac{representation area}{36 ft^{2} } =0.07^{2}$

Solving:

representation area= 0.07²*36 ft²

representation area=0.1764 ft²

The area of the wall on the blueprint is 0.1764 ft²

4 0

4 years ago

Evaluate 7^0 7 0 -7 1 Save

kykrilka [37]

Any number power zero = 1

8 0

3 years ago

*WILLL GIVE BRAINIEST TO COORECT RESPONCE* how do i do this? what is the answer?

Sergio [31]

Answer:

line mo

Step-by-step explanation:

Because the triangle are congrument

RST and MNO are the triangle

RT is a line in the RST triqangle

it is equal to the MO line in MNO

3 0

3 years ago

Can you help me with this question??

Charra [1.4K]

9514 1404 393

Answer:

about 1.4288993 radians

Step-by-step explanation:

The angle to terminal arm A is ...

∠A = arctan((-4/5)/(-3/5)) ≈ 4.0688879 radians

The angle to terminal arm B is ...

∠B = arctan((-1/√2)/(1/√2)) ≈ 5.4977871 radians

Then the angle between the arms is ...

5.4977871 -4.0688879 ≈ 1.4288993 . . . radians

4 0

3 years ago

Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f

schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval: (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{130}{20} = 6.5$

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

$S.D = \sqrt{\frac{233.5}{19}} = 3.50$

b) Standard Error

$= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826$

c) Point estimate for the mean time required for all college is given by the sample mean.

$\bar{x} = 6.5$

d) 90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

$6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)$

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0

4 years ago