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2 years ago

15

Can you please help me? 2.1.3

1 answer:

Nutka1998 [239]2 years ago

6 0

$~~(2I_2)A\\\\\\=2\begin{bmatrix} 1&0\\0&1 \end{bmatrix}\begin{bmatrix} 4&2\\3&-3 \end{bmatrix}\\\\\\=\begin{bmatrix} 2&0\\0&2 \end{bmatrix}\begin{bmatrix} 4&2\\3&-3 \end{bmatrix}\\\\\\=\begin{bmatrix} 8+0&4+0\\0+6&0-6 \end{bmatrix}\\\\\\=\begin{bmatrix} 8&4\\6&-6 \end{bmatrix}$

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3 years ago

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Step-by-step explanation:

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3 years ago

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8 0

4 years ago

The question is attached

DerKrebs [107]

$cos(A - B) = cos A cos B + sin A sin B$

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Hope that helps!

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2 years ago