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2 years ago

Can i have help with this please

Mathematics

2 answers:

vredina [299]2 years ago

7 0

Answer: Heyaa! ~

Your Answer is... 7r²− r −1, Which is B.

Step-by-step explanation:

Subtract the numbers, And then combine like terms,

Solution: 7r²− r −1

Hopefully this helps you! ^

Evgen [1.6K]2 years ago

3 0

Answer:

B) 7r² - r -1

Step-by-step explanation:

(3r² + 7r + 1) + (4r² - 8r - 2)

1. Remove unnecessary parentheses

3r² + 7r + 1 + 4r² - 8r - 2

2. Combine like terms (ex: r and -2r, n and 4n)

7r² - r -1

Therefore, the correct answer is B.

Hope this helps!

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GUYS I NEED HELP PLSSSSSS! Ive been working on this ALL day!

Vika [28.1K]

First, let's write what we know.

We can represent the number of students in the play from each class as L, G, and C. We know that L = 7, and if Gardener has 4 more students than Cho, then G = C + 4.

Then, taking the third line, we can write an inequality:

C < L < G

C < 7 < C + 4

C - 4 < 3 < C

3 < C < 7

If C is greater than 3 and less than 7 and is an integer, than means C is 4, 5, or 6.

Then, we need to find how many students are in the play.

C + L + G

C + 7 + C + 4

2C + 11

So we have our expression for the number of students in the play. Then, we need to find the total number of students. We know that 2C + 11 will be 30% of the total, so if T is the total, we can find T.

0.3T = 2C + 11

(Divide by 3/10 or multiply by 10/3 on both sides)

T = 20/3 C + 110/3

We know from before that C is 4, 5 or 6. We can plug these into our equation here to find which one produces a whole number.

T = 20/3 * 4 + 110/3

T = 190/3

T = 20/3 * 5 + 110/3

T = 210/3

T = 70

T = 20/3 * 6 + 110/3

T = 230/3

We can see here that only when C is 5 will the total be a whole number. That means Mrs. Cho has 5 students in the play. If Mrs. Gardner has 4 more than that, she has 9 students in the play in her class. We now need to figure out the number of student in her class.

The total students are Cho's, Logan's, and Gardner's classes added together. We know that Logan's class is 23 students, so if we subtract that from the total, we can see that Cho's and Gardner's class have 47 students. If Mrs. Cho has 24 students in her class, we can subtract that from the 47, so we know that Mrs. Gardner has 23 students in her class.

4 0

3 years ago

How do you write -4 1/5 as an improper fraction

jekas [21]

-21/5

Multiply 4 and 5, add 1

4 0

3 years ago

Read 2 more answers

Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 7, and b = 18.

zzz [600]

Answer:

none

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

8 0

2 years ago

The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

gladu [14]

We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub

p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
$p= \frac {(x-6)(x+1)(x+4)}{(x-2)}$

7 0

3 years ago

Write 36 as a product from it's prime factors, Write the factors in order, from smallest to largest. Please someone help write a

Darya [45]

2x2x3x3

so 2² x 3²

this is the answer

6 0

4 years ago