Let
x--------> the length side of the square base
h--------> the height of the box
we know that
<u>the volume of the box is equal to</u>

so

<u>the surface area of the box is equal to</u>
(remember that the box is open)
area of the base=
Perimeter of the base=
height=(h) m

substitute

we know that
the value of x can not be negative and the denominator can not be zero
therefore
<u>the answer is</u>
the domain of SA is x> 0
the domain is the interval-------------> (0,∞)
Answer:
2489200
Step-by-step explanation:
First you have 248.92. You also have 10^4
Your equation should look like 248.92 * 10^4
Calculate using a calculator and you should arrive at the answer 2,489,200.
Okay so to get this answer u have too Take 17 and subtract 2 This equals 15, So the answer would be 15, This is how I get my answers at least
Answer:
95°
Step-by-step explanation:
It's a <u>pattern</u>:
<em>135,95,135,135,115,</em><em>95</em><em> </em>
The pattern is<em>...</em> 135, (95) then two more 135's then 115 then the pattern restarts.
I hope this helps!