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Stella [2.4K]
2 years ago
7

1. Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2). Graph BGTS and its image after a translation

along (5,0) and a reflection in the x-axis.​
Mathematics
1 answer:
larisa86 [58]2 years ago
6 0

The image is attached with answer

<h3>What is a Quadrilateral ?</h3>

A quadrilateral is a polygon with four sides , four angles and four vertices.

It is given in the question that

Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2).

A graph has to be drawn of

its image after a translation along (5,0) and a reflection in the x-axis.​

The coordinates after translation and reflection is is B (8, -4), G (6, -3), T (6, -1), and S (7, -2).

The image is attached with the answer .

To know more about Quadrilateral

brainly.com/question/13805601

#SPJ1

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The sum of three consecutive even numbers is 96. What is the smallest of the three numbers
lidiya [134]
The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.


This may help:

96/3=32

32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
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8 0
3 years ago
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Answer:

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3 years ago
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Dima020 [189]

Answer:

P.E.M.D.A.S

P: parenthesis

E: exponent

M: multiplication

D: division

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S; subtraction

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3 years ago
The figure shows two triangles on a coordinate grid:
Firdavs [7]
OK I will answer give me a few minutes I’ll try to be fast and come back to you in the comment section
6 0
3 years ago
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PLS HELP! I NEED TO FIND THE SURFACE AREA OF THIS CYLINDER!
Contact [7]

Exact Surface Area = 378pi

Approximate Surface Area = 1186.92

The approximate surface area uses pi = 3.14

The units are cm^2 or "square cm".

=========================================================

Work Shown:

SA = surface area of cylinder

SA = 2*pi*r^2 + 2*pi*r*h

SA = 2*pi*7^2 + 2*pi*7*20

SA = 2*pi*49 + 2*pi*140

SA = 2*49*pi + 2*140*pi

SA = 98pi + 280pi

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SA = 378*3.14

SA = 1186.92 ..... approximate surface area

----------

Side note: The diameter 14 cuts in half to get the radius r = 7

3 0
3 years ago
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