Answer:
Following is the program in C++ Language
#include <iostream> // header file
using namespace std; // namespace std
int main() // main method
{
int n; // variable declaration
cout<<" Please enter the number :";
cin>>n; // Read the number
if(n>0) // check the condition when number is positive
{
cout<<n<<endl<<"The number is Positive"; // Display number
}
else if(n<0) // check the condition when number is Negative
{
cout<<n<<endl<<"The number is Negative";// Display number
}
else // check the condition when number is Zero
{
cout<<n<<endl<<"The number is Zero";// Display number
}
return 0;
}
Output:
Please enter the number:
64
The number is Positive
Explanation:
Following are the description of the program
- Declared a variable "n" of int type.
- Read the value of "n" by user.
- Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
- Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
- Finally if both the above condition is fail it print the message " The number is Zero"
The correct debugged code is attached below
<h3>What is a leap year </h3>
A leap year is a year with 366 days and this year occurs once every 4 years. The debugged code line of code of the program written, is as attached below. because the line of code in the question lacks some functions and symbols
Hence we can conclude that the correct debugged code is attached below.
Learn more about Python coding : brainly.com/question/16397886
#SPJ1
Crunchyroll or my anime list. Both of these work.
Hope this helps you
Answer:
Ans1.
double calc_a;
calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);
Ans2.
double calc_b;
calc_b=((12.0/3.0)-(2.0*4.0));
Ans 3.
double calc_c;
calc_c=(Math.sqrt(16.0)*(7.0+9.0));
Ans 4.
double calc_d;
calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);
Explanation:
The expressions are done with Java in answer above.
