If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Option B is correct.
Step-by-step explanation:
We need to solve:
We know that:
Applying the above rule:
So, Option B is correct.
Keywords: Solving with Exponents
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<span>25x2 = 16
x^2 = 16/25
</span>x^2 = 4^2/5^2
<span>x = 4/5
</span>
Answer:
D.
Step-by-step explanation:
You see, this is simple division. Let's divide it.
-35/-7 = -42
_____________________
Don't let the other options confuse you. negative dividing is just the same as regular, just negative ^^
Answer:
A
Step-by-step explanation:
The two angles in the triangle in the question are 58 degrees and 54 degrees.
Three angles in a triangle add up to 180 degrees
58 + 54 + x = 180
112 + x = 180
subtract 112 on both sides
x = 180 - 112 = 68 degrees
Only option A has a triangle that has the same angles, thus triangles are similar.
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