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Assoli18 [71]
3 years ago
13

The theoretical probability of an event occurring is 2/5 Which best describes the experimental probability associated with this

event?
Mathematics
2 answers:
max2010maxim [7]3 years ago
6 0
The answer is out of every 5 trials, the desired out come will be approximately 2 times. 
Triss [41]3 years ago
3 0

Answer:

Out of every 5 trials, the desired outcome will occur approximately 2 times.

Step-by-step explanation:

Consider the provided information.

Theoretical probability is a likelihood determined by reasoning.

It can be written as the number of favorable outcomes divided by the total number of possible outcomes.

Or we can say that the numerator represents the favorable outcomes and denominator represents the total number of possible outcomes.

Thus, we can say that 2/5 represents: Out of every 5 trials, the desired outcome will occur approximately 2 times.

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Which equation represents a circle?<br><br> A. <br><br><br> B. <br><br><br> C. <br><br><br> D.
mart [117]

Answer:

??

Step-by-step explanation:

how you want the people answer if we can't see anything lol no offense...

8 0
3 years ago
Read 2 more answers
3^2 dived (-4+5)^2-11+2^3 hope you can answer
seropon [69]

Answer:

3^2  = 9

(-4+5)^2-11+2^3 = -2

-2/9 or -9/2 ... re-read question is 3^2 dividing into (-4+5)^2-11+2^3

or the other way around... I think that there is a missing word...

3^2 "divided into"

vs 3^2 "divided by"

Step-by-step explanation:

7 0
3 years ago
25pts awarded and brainliest awarded, plz help asap!!!!!!
ivann1987 [24]

Answer:

B. f(-1)=6

C.  The domain of f(x) is the set {-2.-1,0,1,2,3,4,5,6}

Step-by-step explanation:

To find f(5) from the table means, the y-value that corresponds to x=5.

This value is 12.

This implies that:

f(5)=12

Also the y-value that corresponds to -1 is 6.

Hence f(-1)=6

The domain of f(x) are the set of all the x-values.

The domain is : {-2.-1,0,1,2,3,4,5,6}

The range for f(x) is the set of all the corresponding y-values.

From the table, the range is: {5,6,7,8,9,10,11,12,13}

4 0
3 years ago
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
Please help I will really appreciate it
Veronika [31]
Hi!
Where’s the question.
8 0
2 years ago
Read 2 more answers
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