The slope formula is y2-y1 divided by x2- x1 so -8-6=-14 and -1+3=2
-14/2 =-7
1.3y +3.2 = 1.3y +3.2
we notice that both sides of the equation are identical. So substitute y with any value and the equation would still be correct.
y has infinite solutions.
Complete the table for the function y = 0.1^x
The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.
* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).
* 0.1^-1 = 1/0.1 = 10
* 0.1^0 = 1 : (Remember this rule: a^0 = 1)
* 0.1^1 = 0.1
Our list of values: 100, 10, 1, 0.1
Now, we can plug these values into your table:
![\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26y%5C%5C2%2610%5C%5C1%2610%5C%5C0%261%5C%5C1%260.1%5Cend%7Barray%7D%5Cright%5D)
The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]
I hope this helped!
Answer:
A, C are true . B is not true.
Step-by-step explanation:
Mean of a discrete random variable can be interpreted as the average outcome if the experiment is repeated many times. Expected value or average of the distribution is analogous to mean of the distribution.
The mean can be found using summation from nothing to nothing x times Upper P (x) , i.e ∑x•P(x).
Example : If two outcomes 100 & 50 occur with probabilities 0.5 each. Expected value (Average) (Mean) : ∑x•P(x) = (0.5)(100) + (0.5)(50) = 50 + 25 = 75
The mean may not be a possible value of the random variable.
Example : Mean of possible no.s on a die = ( 1 + 2 + 3 + 4 + 5 + 6 ) / 6 = 21/6 = 3.5, which is not a possible value of the random variable 'no. on a die'
Answer:
12
Step-by-step explanation:
-4 * -3
12
When you multiply two negatives, you get a positive number.
Hope this helps ^-^
