Question

What is an equation of a line that passes through the point of (-8 2) and (-4,-3)

Answer 1

Answer:

y = -5/4x -8

Step-by-step explanation:

$(-8,2)=(x_1 ,y_1)\\(-4 ,-3) = (x_2 ,y_2)\\\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-2}{x-(-8)}= \frac{-3-2}{-4-(-8)}\\ \\\frac{y-2}{x+8}= \frac{-5}{-4+8} \\ \\\\\frac{y-2}{x+8} = \frac{-5}{4}\\ \\Cross\:Multiply \\4(y-2) = -5(x+8)\\\\4y-8 =- 5x-40\\\\4y = -5x-40+8\\\\4y =- 5x-32\\\\\frac{4y}{4} = \frac{-5x}{4} + \frac{-32}{4} \\\\y = -\frac{5}{4}x-8$