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rusak2 [61]
2 years ago
6

Graph the inequality. y > |x-2| -5

Mathematics
1 answer:
Neporo4naja [7]2 years ago
3 0

Here is the graph! I hope this helps!

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Simplify to create an equivalent expression.<br> 8(a+2)+2(2+3a)=
Alchen [17]

Answer:

14a + 20

Step-by-step explanation:

8(a + 2) + 2(2 + 3a)

expand the bracket

8a + (8*2) + (2*2) + (2*3a)

8a + 16 + 4 + 6a

bring like terms together

8a + 6a + 16 + 4

14a + 20

3 0
3 years ago
PLEASE HELP ASAP!! VERY IMPORTANT!!!!! (NUMBER 15!!)
maria [59]
The answer is c cause the answer is 16,741.55ft^2 and c is the closest to it
5 0
3 years ago
Last year, Mr. Engle's total income was $52,000, while his total expenses were $53,800. Use the expression I-E/12, where I repre
olga55 [171]
Given Mr. Engle’s total income, I = $52,000 and total expenses, E = $53,800, solving for average difference between income and expenses per month:
(I-E)/12 = ($52,000 - $53,800)/12
(I-E)/12 = - $1,800/12
(I-E)/12 = -$150
This means that Mr. Engle’s expenses exceed his income by an average of $150 each month in the said year.
3 0
3 years ago
Read 2 more answers
Teresa plans to attend college in 3 years. She will need $13,600 for the first-year cost. Her uncle gave her a special gift of $
timofeeve [1]

Answer:

100$ per month

Step-by-step explanation:

8 0
3 years ago
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
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