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Tom [10]
2 years ago
5

A stationary police officer directs radio waves emitted by a radar gun at a vehicle moving toward the officer. Compared to the e

mitted radio waves, the radio waves reflected from the vehicle and received by the radar gun have a.
Physics
1 answer:
strojnjashka [21]2 years ago
8 0

Compared to the emitted radio waves, the radio waves reflected from the vehicle and received by the radar gun have a<u> higher frequency.</u>

<u></u>

<h3>What is the frequency?</h3>

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second. Its unit is Hz. Frequency is given by the formula as,

A moving car is targeted by radio waves sent from a radar gun by a police officer standing still.

The radio waves reflected off the vehicle and picked up by the radar gun have a greater frequency than the radio waves that were transmitted.

A stationary police officer directs radio waves emitted by a radar gun at a vehicle moving toward the officer.

Compared to the emitted radio waves, the radio waves reflected from the vehicle and received by the radar gun have a<u> higher frequency.</u>

Hence the higher frequency is the correct answer for blanks.

To learn more about the frequency refer;

brainly.com/question/14926605

<u></u>

#SPJ1

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A peregrine falcon dives at a pigeon. The falcon starts with zero downward velocity and falls with the acceleration of gravity.
Reptile [31]

Answer:

t = 3.94 s

Explanation:

This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:

h = v_{i}t + \frac{1}{2}gt^2

where,

h = height = 76 m

vi = initial speed of falcon = 0 m/s

t = time required = ?

g = acceleration due to gravity = 9.81 m/s²

Therefore,

76\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\t^2 = \frac{(2)(76\ m)}{9.8\ m/s^2}\\\\t = \sqrt{ 15.49\ s^2}\\

<u>t = 3.94 s</u>

5 0
3 years ago
Tripling the displacement from equilibrium of an object in simple harmonic motion will change the magnitude of the object’s maxi
SVEN [57.7K]
A (max)= A (2pi/T)
a (max)= maximum acceleration
A= amplitude
T= periodic time

by definition, amplitude is the displacement from equillibrium point.

we see that maximum acceleration is directly proportional to the amplitude. so tripling the amplitude will triple the maximum acceleration.
5 0
4 years ago
PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!
DaniilM [7]
The correct answer would be to express large and small numbers.
5 0
3 years ago
A mechanical wave is created when a medium ____, or moves back and forth or up and down
Zielflug [23.3K]
I think it is traverse wave
6 0
4 years ago
Read 2 more answers
A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass
vazorg [7]

Explanation:

Impulse = change in momentum

FΔt = Δp

(53 N) (15 s) = Δp

Δp = 795 kg m/s

For constant mass:

Δp = m Δv

795 kg m/s = (12 kg) Δv

Δv = 66.25 m/s

Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.

8 0
3 years ago
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