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Gwar [14]
3 years ago
12

A student is asked to determine the work done on a block of wood when the block is pulled horizontally using an attached string.

The student is supplied with a spring scale, a stopwatch, and a meterstick. Which of the following graphical analysis techniques will allow the student to determine the work done on the block by the string?
A. Graphing the force as a function of time and calculating the slope
B. Graphing the force as a function of time and calculating the area under the curve
C. Graphing the force as a function of distance and calculating the slope
D. Graphing the force as a function of distance and calculating the area under the curve

Physics
2 answers:
Lerok [7]3 years ago
5 0

Answer:

D. Graphing the force as a function of distance and calculating the area under the curve.

Explanation:

Svet_ta [14]3 years ago
3 0

Answer:

The correct option is (D). "Graphing the force as a function of distance and calculating the area under the curve"

Explanation:

1) As we know from the definition of Work done which is Work = Force × Displacement. Time doesn't have any use in the mentioned equation and thus the stop watch is of no use to us.

2) Using the meter stick, we can measure the distance for which the block is pulled horizontally i.e "Displacement"

3) Using the spring scale, we can calculate the "Force" applied on the block of wood to move it horizontally.

4) For example, lets say that for a constant force of 4 Newtons, the wooden block is pulled horizontally 4 meters. Plotting Force vs Displacement on a graph would yield a horizontal line as shown in the attachment. Area under the F vs D graph will give us the total work done.

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6 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

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Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

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=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
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Answer:

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