Answer:
The correct option is (D). "Graphing the force as a function of distance and calculating the area under the curve"
Explanation:
1) As we know from the definition of Work done which is Work = Force × Displacement. Time doesn't have any use in the mentioned equation and thus the stop watch is of no use to us.
2) Using the meter stick, we can measure the distance for which the block is pulled horizontally i.e "Displacement"
3) Using the spring scale, we can calculate the "Force" applied on the block of wood to move it horizontally.
4) For example, lets say that for a constant force of 4 Newtons, the wooden block is pulled horizontally 4 meters. Plotting Force vs Displacement on a graph would yield a horizontal line as shown in the attachment. Area under the F vs D graph will give us the total work done.
Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3 = 5 3 2
x_{f} = 45 m
we substitute
v = 15 m / s
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
Which gives;
F₀ = T₂·sin(37°)
Which gives;
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Learn more about equilibrium of forces here: