Which of the following must be true for hydropower to work?

What happens when you create a variable in a video game program?

gulaghasi [49]

Answer:

A lot can happen, depending on the use of the variable

Explanation:

Lets create a position variable, a common variable in games.

Vector3 position = new Vector3(0, 0, 0);

The above variable initialization creates a new Vector3 object. The Vector3 class contains 3 properties, X, Y, and Z. When you assign the variable 'position' the new Vector3 object, the variable 'position' contains an instance of Vector3 where

X = 0,

Y = 0,

and Z = 0.

The variable 'position' can be used to set the position of a player, or an object.

We can reuse this variable when you want the object or player to move.

position.X = 29

position.Y = -14

position.Z = 47

now the object/player's position is (29, -14, 47).

Variables can be used for basically everything you need in programming, from storing a position, to storing the result of a complex math equation.

7 0

2 years ago

Given an array A of size N, and a number K. Task is to find out if it is possible to partition the array A into K contiguous sub

Dennis_Churaev [7]

Answer: First lets solve the Prerequisite part

Lets say we have an input array of N numbers {3,2,5,0,5}. We have to find number of ways to divide this array into 3 contiguous parts having equal sum. So the output for the above input array will be 2 as there are 2 ways to divide the array. One is (3,2),(5),(0,5) and the other is (3,2),(5,0),(5).

Following are the steps to achieve the above outcome.

Let p and q point to the index of array such that sum of array elements from 0 to p-1 is equal to sum of array elements from p to q which is equal to the sum of array elements from q+1 to N-1.
If we see the array we can tell that the sum of 3 contiguous parts is 5. So the condition would be that sum of all array elements should be equal to 5 or sum of each contiguous part is equal to sum of all array elements divided by 5.
Now create 2 arrays prefix and postfix of size of input array. Index p of prefix array carries sum of input array elements from index 0 to index p. Index q of postfix array carries sum of input array elements from index p to index N-1
Next move through prefix array suppose at the index p of prefix array : value of prefix array == (sum of all input array elements)/5.
Search the postfix array for p index found above. Search it starting from p+2 index. Increment the count variable by 1 when the value of postfix array =(sum of all input array elements)/5 and push that index of postfix array into a new array. Use searching algorithm on new array to calculate number of values in postfix array.

Now lets solve the main task

We have an array A of size N and a number K. where A[]= {1,6,3,4,7} N=5 and K=3. We have to find if its possible to partition A into 3 contiguous subarrays such that sum of elements in each subarray is the same. It is possible in this example. Here we have 3 partitions (1,6),(3,4),(7) and sum of each of subarrays is same (1+6) (3+4) (7) which is 7.

Following are the steps to achieve the above outcome.

In order create K contiguous subarrays where each subarray has equal sum, first check the condition that sum of all elements in the given array should be divisible by K. Lets name another array as arrsum that will be the size of array A. Traverse A from first to last index and keep adding current element of A with previous value in arrsum. Example A contains (1,6,3,4,7} and arrsum has {1,7,10,14,21}
If the above condition holds, now check the condition that each subarray or partition has equal sum. Suppose we represent sum1 to sum of all element in given array and sum2 of sum of each partition then: sum2 = sum2 / K.
Compare arrsum to subarray, begining from index 0 and when it becomes equal to sum2 this means that end of one subarray is reached. Lets say index q is pointing to that subarray.
Now from q+1 index find p index in which following condition holds: (arrsum[p] - arrsum[q])=sum2
Continue the above step untill K contigous subarrays are found. This loop will break if, at some index, sum2 of any subarray gets greater than required sum2 (as we know that every contiguous subarray should contain equal sum).

A easier function Partition for this task:

int Partition(int A[], int N, int k) // A arra y of size N and number k

{ int sum = 0; int count = 0; //variables initialization

for(int j = 0; j < N; j++) //Loop that calculates sum of A

sum = sum + A[j];

if(sum % k != 0) //checks condition that sum of all elements of A should be //divisible by k

return 0;

sum = sum / k;

int sum2 = 0; //represents sum of subarray

for(int j = 0; j < N; j++) // Loop on subarrays

{ sum2=sum2 + A[j];

if(sum2 == sum) { //these lines locates subarrays and sum of elements //of subarrays should be equal

sum2 = 0;

count++; } }

/*calculate count of subarrays whose

sum is equal to (sum of complete array/ k.)

if count == k print Yes else print No*/

if(count == k)

return 1;

else

return 0; }

6 0

3 years ago

Create a derived class called Car that inherits from Vehicle. The constructor should call the base class constructor, with 4 for

Vitek1552 [10]

Answer:

Hi there Foodalexandre! The question is good to revise knowledge on the concepts of classes and inheritance. Please find the answer with explanation below.

Explanation:

We can use a number of different object-oriented programming languages to implement this solution in, such as Java, C++, Ruby, etc. I have chosen to use Python as the language to implement because of the ease with which it can be used. First, I have defined the Vehicle class based on the description from the question, where the constructor (the __init__ method) initializes the door count and the engine sound, and the original Move() method belonging to the Vehicle class is defined. Then I define the Car class which inherits from the Vehicle class making it inherit the Vehicle properties, and initialize the Car class to have door count of 4 and engine sound as 'rrrrrr'. Defining the Move() method again in the Car class overrides the one in the Vehicle class, and the RoadTrip() method is added to return the string as requested in the question.

class Vehicle(object):

def __init__(self, door_count, engine_sound):

door_count: door_count

engine_sound: engine_sound

def Move() :

return ‘rrrrrr’

class Car(Vehicle):

def __init__(self, door_count, engine_sound):

super().__init__(4, ‘rrrrrr’)

def Move():

return ‘vrumm’

def RoadTrip() :

return “Not a care in the world”

3 0

3 years ago

Write a program to input elements of 4*3matrix and prints its elements properly using array

Harlamova29_29 [7]

Answer:

Step by step explanation:

7 0

2 years ago

Create an application for a library and name it FineForOverdueBooks. TheMain() method asks the user to input the number of books

andrew11 [14]

Answer:

//The Scanner class is imported which allow the program to receive user input

import java.util.Scanner;

//Class Solution is defined to hold problem solution

public class Solution {

// The main method which signify the begining of program execution

public static void main(String args[]) {

// Scanner object 'scan' is defined to receive input from user keyboard

Scanner scan = new Scanner(System.in);

// A prompt is display asking the user to enter number of books

System.out.println("Please enter number of books: ");

// the user response is assigned to numberOfBook

int numberOfBook = scan.nextInt();

// A prompt is displayed asking the user to enter the number of days over due

System.out.println("Please enter number of days over due: ");

// the user response is assigned to numberOfDaysOverDue

int numberOfDaysOverDue = scan.nextInt();

//displayFine method is called with numberOfBook and numberOfDaysOverDue as arguments

displayFine(numberOfBook, numberOfDaysOverDue);

}

//displayFine method is declared having two parameters

public static void displayFine(int bookNumber, int daysOverDue){

// fine for first seven days is 10cent which is converted to $0.10

double firstSevenDay = 0.10;

// fine for more than seven days is 20cent which is converted to $0.20

double moreThanSevenDay = 0.20;

// the fine to be paid is declared

double fine = 0;

// fine is calculated in the following block

if(daysOverDue <= 7){

//the fine if the over due days is less than or equal 7

fine = bookNumber * daysOverDue * firstSevenDay;

} else{

// the extra days on top of the first seven days is calculated and assigned to extraDays

int extraDays = daysOverDue - 7;

//fine for first seven days is calculated

double fineFirstSevenDays = bookNumber * 7 * firstSevenDay;

// fine for the extradays is calculated

double fineMoreThanSevenDays = bookNumber * extraDays * moreThanSevenDay;

// the total fine is calculated by adding fine for first seven days and the extra days

fine = fineFirstSevenDays + fineMoreThanSevenDays;

}

// The total fine is displayed to the user in a nice format.

System.out.printf("The fine for " + bookNumber + " book(s) for " + daysOverDue + " day(s) is: $%.02f", fine);

}

Explanation:

The program first import Scanner class to allow the program receive user input. Then the class Solution was defined and the main method was declared. In the main method, user is asked for number of books and days over due which are assigned to numberOfBook and numberOfDaysOverDue. The two variable are passed as arguments to the displayFine method.

Next, the displayFine method was defined and the fine for the first seven days is calculated first if the due days is less than or equal seven. Else, the fine is calculated for the first seven days and then the extra days.

The fine is finally displayed to the user.

4 0

3 years ago