Question

Identify the expressions for which limits exist.

Answer 1

Answer:

Step-by-step explanation:

Limits exist for:

$\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x}$ = $\frac{(x-4)(x+3)}{4-x}$ = ( - 1 )( x + 3 ) = - 7

$\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x}$ = $\frac{(x+4)(x-2)}{2-x}$ = ( - 1 )( x + 4 ) = - 6

$\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4}$ = $\frac{(x+5)(x-2)}{(x+2)(x-2)}$ = $\frac{x+5}{x+2}$ = $\frac{7}{4}$