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Marysya12 [62]
2 years ago
13

Identify the expressions for which limits exist.

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
5 0

Answer:

Step-by-step explanation:

Limits exist for:

\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x} = \frac{(x-4)(x+3)}{4-x} = ( - 1 )( x + 3 ) = - 7

\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x} = \frac{(x+4)(x-2)}{2-x} = ( - 1 )( x + 4 ) = - 6

\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4} = \frac{(x+5)(x-2)}{(x+2)(x-2)} = \frac{x+5}{x+2} = \frac{7}{4}

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