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2 years ago

Write 508/1000 as a decimal

Mathematics

1 answer:

natka813 [3]2 years ago

4 0

Answer:

0.508

Hope this helps!

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HELP EASY ASAP MULTIPLE CHOICE

Rudik [331]

Answer:

It's the first one 18/3 =6

Step-by-step explanation:

This is the only answer that has all integers or whole numbers. Hope this helps!

5 0

2 years ago

Read 2 more answers

Janelle graphed a line through (−6, 5) that had a slope of −79. What is the y-coordinate of a point on the line that has an x-co

jeyben [28]

Answer:

The value of the y-coordinate is -706

Step-by-step explanation:

The equation of a straight line is;

y = mx + c

where m is slope and c is t-intercept

Given the slope, we can write the equation as;

y = -79x + c

we need to get c

Just put in the x and y values of the given point

X = -6 and y = 5

5 = -79(-6) + c

5 = 474 + c

c = 5-474 = -469

So the complete equation of the line would

be ;

y = -79x - 469

To get the y-coordinate of the point, just insert the x value into the equation;

y = -79(3) - 469

y = -237 - 469 = -706

4 0

2 years ago

16x − 7 ≤ −71<br><br> find x

My name is Ann [436]

16x-7≤-71
Add 7 to both sides
16x≤-64
Divide both sides by 16
x≤ -4

Hope this helps! :)

7 0

3 years ago

Give a step by step instructions

Lina20 [59]

Answer:

1. X-intercept is 5 Y-intercept is 4 (Red Line)

2. X-intercept is 1 Y-intercept is 2 (Blue Line)

3. X-intercept is -2 Y-intercept is 4 (Green Line)

Step-by-step explanation:

DESMOS graphing calculator. Here is the graph showing my work:

7 0

2 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago