Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
All of the angles would be acute angles because they are less then 90 degrees
Answer:
2x^7
Step-by-step explanation:
Multiply
x
^4 by x
^3 by adding the exponents.
30= 3*10
30= 3*2*5
48= 12*4
48= 3*4*4
48= 3*2*2*2*2
60= 3*20
60= 3*10*2
60= 3*2*5*2
The GCF is 3*2 because all 3 numbers contain a 3 and a 2 in their prime factorizations.
Final answer: 6
Answer:
30
Step-by-step explanation:
You can use the triangle area theorem-
15x4(/2)=30