Answer:
The number of trucks and sedans can be
(0 trucks ,26 sedans)
(8 trucks ,21 sedans)
(24 trucks ,11 sedans)
(25 trucks ,1 sedans)
(32 trucks ,6 sedans)
(16 trucks ,16 sedans)
Step-by-step explanation:
Given:
The cost for trucks =$5
The cost for sedans =$8
The total amount collected = $208
To Find:
Number of trucks and sedans passed through the toll booth =?
Solution:
Let the number of trucks be x and the number of sedans be y
Then
5x + 8y = 208-------------------------------(1)
By Trail and error method
5(0) + 8(26) = 208
5(8) + 8(21) = 208
5(24) +8(11) =208
5(25) + 8(1) = 208
5(32) + 8(6) =208
5(16) + 8(16) = 208
I don’t see an attachment for a diagram
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
Answer:
Yes it can be solved.
Step-by-step explanation:
I did this stuff in like 4th grade lollll
Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
