Answer:
Perimeter of rectangle 1=4x+4
Perimeter of rectangle 2=4x+4
Step-by-step explanation:
Two squares with the same dimension
Square 1: let length=x
Square 2: let length=x
Since they have same dimensions
He added two inches to the length of square 1 to make it a rectangle
Rectangle 1: width=x, length=x+2
Perimeter=2(l+w)
=2{(x+2)+x}
=2(x+2+x)
=2(2x+2)
=4x+4
He added two inches to the width of square 2 to make it a rectangle
Rectangle 2: length=x, width=x+2
Perimeter=2(l+w)
=2{(x+(x+2)}
=2(x+x+2)
=2(2x+2)
=4x+4
The two rectangles have equal perimeter
The coordinate for A, B, C, and D: (Current coordinates)
A: (-1, 4)
B: (-5, 8)
C: (-5, 4)
D: (-4, 2)
Once we reflect acorss the y-axis the coordinates become:
A': (1, 4)
B': (5, 8)
C': (5, 4)
D': (4, 2)
In this situation the coordinates just become positive.
I hope this helps!
Answer:
ya i dont either
Step-by-step explanation:
Answer:
x=148
Step-by-step explanation:
First, find the missing angle by subtracting 100+48 from 180 (all of the angles in a triangle add up to 180). Then, subtract that from 180 (the angles are a linear pair, so they are supplementry, so they add up to 180) x+32=180.
x=148.
(お役に立てれば！)
First answer haha~ I think I answered all your questions so far ;)
