Answer:
x = 4,
x = -2
Step-by-step explanation:
( x - 4 ) ( x + 2 ) = 0
Find out when the equation is 0,
When x = 4,
substitute in 4 for x,
( 4 - 4 ) ( 4 + 2 ) = 0
(0) ( 6) = 0 (any number multiplied by 0 is 0).
When x = -2
Substitue in -2 for x,
( -2 - 4 ) ( -2 + 2 ) = 0
(-6) (0) = 0 (again, any number multiplied by 0 is 0).
Hm...maybe searching it up on google can help you...
Answer:
The system has one solution.
Step-by-step explanation:
To find the number of solutions of the system, we equal both equations for y.
If we have ax = b, in which both a and b are different of 0, we have one solution.
If both a and b are 0, we have infinite solutions.
If a is 0 and b is not, there are no solutions.
y=6/7x-8 and y=7/9x+10/9
So
Both a and b are different of 0, so the system has one solution.
Please use " ^ " to indicate exponentiation: x^2 + 3x - 4 = 0
Here, a = 1, b = 3 and c = -4.
The formula for the discriminant is b^2 - 4(a)(c).
Substituting the given values of a, b and c, we get:
(3)^2 - 4(1)(-4)
Evaluating this, we get 9 + 16 = 25.
The discriminant is 25.
-3 plus or minus √25
Taking this further, x = ------------------------------------
2
-3 plus or minus 5
or: x = -------------------------------- => {-4, 1} (solutions)
2
If f(1) =5-2(1)
F(2)=5-2(2)
