As We can see that point J is on (-2,5) and L is on (-2,-2)
So we know that distance cannot be in negative, thus
Distance between J and L =5+2=7 units
JL=7
Answer:
your answer is c l hipe this helps u
9+10 = 21 you stupid you stupid no I’m not
The slope-point form of a line:

The slope-intercept form of a line:

1.

Substitute

2.

Substitute

3.

4.
