Step-by-step explanation:
there is something wrong with your question.
there is no parallelogram with 8 and 6 ft side lengths that has an area of 54 ft².
the maximum area of a parallelogram with 8 and 6 ft side lengths is 48 ft². and that is a rectangle 8×6 as a special form of a parallelogram.
the area of any parallelogram is calculated
Ap = base length × height
and height is the length of the line perpendicular to the base line to one of the corners on the opposite side (as long as the base line).
if Ap = 54, and the base length is 8, this means
54 = 8 × height
height = 54/8 = 6.75 ft
but the height can only be the length of a side connected to the base line or less. not longer.
and in our example here, this connected side is 6. so, the height can only be 6 or less. not 6.75.
so, there must be something wrong with your numbers.
once you get the actual numbers, use my approach above with them (replace whatever number is wrong here by the true value).
For this case we have the following relationship:
(x / 5280) = (7/100)
From this relationship we must clear the value of x.
Clearing we have:
x = (7/100) * (5280)
Calculating we have:
x = 0.07 * 5280
x = 369.6 feet
Answer:
it does rise in a horizontal distance of 1 mile about:
x = 369.6 feet
Answer:
y = 2x
the rise is the 2, and the the run is positive 1, because with graphing its always rise/run, and if there isn't anything below it, it is 2x/1
Answer: fluffy = 33yrs
Spot = 19 yrs
Skampy = 39 yrs
Step-by-step explanation:
Let fluffy = x
Spot = y
Skampy =z
x + y + z = 91 -------1
x -14 =y ------2
z = x + 6 --------3
Put eqn 2 and 3 in eqn 1
x + x - 14 + x + 6 = 91
3x = 99
x = 33
y = 33-14= 19
z = 33+6 = 39
<u><em>≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈</em></u>
<u><em /></u>
The reason i say this is because i don't really want to run into something that i don't know much about. I do know quite a bit about extinct animals more than i do aliens. So, that's my reasoning.
<em><u>≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈</u></em>
<em><u></u></em>
<em><u></u></em>
<em><u></u></em>