Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths
is

So the solution here is

Since It's parallel to <span>y=5x-9 the slope of this new line is 5
so the equation looks like </span><span>y=5x+b
to find be we just replace x by 2 and y by 3
3=10-b so b = -7
the equation is </span><span>y=5x-7</span>
I believe C. Because it provides a more meaningful explanation
Standard Form: 79,031
Expanded Form: 70,000 + 9,000 + 30 + 1
65 times 5 is 325 then u take 1000 and minus 325 from it and end up with 675