2 years ago

Need help with this question p

Mathematics

1 answer:

patriot [66]2 years ago

7 0

Answer:

4x² + 12x + 9

Step-by-step explanation:

<h3>Using identity: </h3>

(a +b)² = a² + 2ab + b²

Here, a = 2x & b = 3

(2x +3 )² = (2x)² + 2*2x*3 + 3²

= (2x*2x) + 12x + 3*3

= 4x² + 12x + 9

You might be interested in

Simplify the expression:<br> -6x-4x-10+3

tangare [24]

Answer:

-10x-7

Step-by-step explanation:

6 0

3 years ago

Seven less than one-third of a number is 5

miskamm [114]

22 would be the answer. You reverse the equation so you multiply 3 and add 7 5x3 = 15 15+7= 22

3 0

3 years ago

Read 2 more answers

Pls help for Algebra 11b = 143

ziro4ka [17]

Answer:

b = 13

Step-by-step explanation:

Divide 143 by 11

8 0

3 years ago

Read 2 more answers

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

3 years ago

Easy problems I'm having trouble remembering how to do!

beks73 [17]

<h2>Answer:</h2>

1. - 2°C + 4°C

= 2°C.

2. 3/4 × 4

= 3pounds.

7 0

2 years ago