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Mice21 [21]
2 years ago
13

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

Mathematics
1 answer:
zlopas [31]2 years ago
6 0

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

Step-by-step explanation:

Un par ordenado es un elemento de la forma (x,f(x)), donde x es un elemento del dominio de la función, mientras f(x) es la imagen de la función evaluada en x. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

x \rightarrow f(x)

Dado que f(x) es una función polinómica, existe una imagen para todo elemento x. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

f(0) = 0^{3}-2\cdot (0)^{2}-2

f(0) = -2

(0, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 1

f(1) = 1^{3}-2\cdot (1)^{2}-2

f(1) = -3

(1, -3) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 2

f(2) = 2^{3}-2\cdot (2)^{2}-2

f(2) = -2

(2, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 3

f(3) = 3^{3}-2\cdot (3)^{2}-2

f(3) = 7

(3, 7) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

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