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cestrela7 [59]
1 year ago
12

Please help me with the problem below.

Mathematics
2 answers:
xxTIMURxx [149]1 year ago
3 0

Answer:

67.5 cm^2

Step-by-step explanation:

we know the length and width of the rectangle and the triangle in the compound shape.

The area of the rectangle is 10 times 5 = 50

the area of the triangle is

17-10 = 7

7 times 5 is 35

35/2 = 17.5

50 plus 17.5 = 67.5 cm^2

IrinaK [193]1 year ago
3 0

Answer: 67.5

Step-by-step explanation:  Since this is a irregular shape, you have to split the two shapes.  The rectangles area is 50, and the triangles is 17.5.

To find the area of a triangle multiply 1/2 × base × height

To find the area of a rectangle multiply base × height

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Korvikt [17]

No - It is a function.


A relation which is not a function has more than 1 output for an input.

7 0
3 years ago
-8x^2-3x+5+2x^2+7x-5
denis-greek [22]
-6x^2+4x

my reasoning:
eliminate the opposites (5 & -5)
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8 0
3 years ago
Please helppp with this​
kiruha [24]

Answer:

3 one

Step-by-step explanation:

7 0
3 years ago
The equation for the cost in dollars of producing automobile tires is c = 0.000015x2 - 0.03x + 35, where x is the number of tire
statuscvo [17]
The cost function is
c = 0.000015x² - 0.03x + 35
where x = number of tires.

To find the value of x that minimizes cost, the derivative of c with respect to x should be zero. Therefore
0.000015*2x - 0.03 = 0
0.00003x = 0.03
x = 1000

Note:
The second derivative of c with respect to x is positive (= 0.00003), so the value for x will yield the minimum value.

The minimum cost is
Cmin = 0.000015*1000² - 0.03*1000 + 35
          = 20

Answer:
Number of tires = 1000
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3 0
3 years ago
People are entering a building at a rate modeled by f (t) people per hour and exiting the building at a rate modeled by g (t) pe
erastova [34]

Answer:

The correct option is D) f'(t)-g'(t) > 0

Step-by-step explanation:

Consider the provided information.

People are entering a building at a rate modeled by f (t) people per hour and exiting the building at a rate modeled by g (t) people per hour,

The change of number of people in building is:

h(x)=f(t)-g(t)

Where f(t) is people entering in building and g(t) is exiting from the building.

It is given that "The functions f and g are non negative and differentiable for all times t."

We need to find the the rate of change of the number of people in the building.

Differentiate the above function with respect to time:

h'(x)=\frac{d}{dt}[f(t)-g(t)]

h'(x)=f'(t)-g'(t)

It is given that the rate of change of the number of people in the building is increasing at time t.

That means h'(x)>0

Therefore, f'(t)-g'(t)>0

Hence, the correct option is D) f'(t)-g'(t) > 0

4 0
2 years ago
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