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Mama L [17]
4 years ago
5

Please help me with a, and B,

Mathematics
1 answer:
Masteriza [31]4 years ago
7 0

Develop a passion for learning. If you do, you will never cease to grow.

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PLEASE HELP I HAVE TO TURN THIS IN IN 30 MINUTES
ryzh [129]
8(5t-2)
is the answer factored completely
4 0
3 years ago
Read 2 more answers
A blackboard has an area of 28 and a perimeter of 22 ft. What are the dimensions of the board?
Alex787 [66]

Answer:

the ancer is c

Step-by-step explanation:

Answer:

Option (c) is correct.

Dimension of board is 4 ft by 7 ft.

Step-by-step explanation:

Given : A blackboard has an area of 28 feet squared and a perimeter of 22 ft.

We have to find the dimension of blackboard and choose the correct option from given options.

Since blackboard is in shape of rectangle thus,

Area of blackboard is 28 feet²

That is, Area of rectangle =  28 feet²

We know Area of rectangle = length × Breadth

substitute, we get,

28 = length × Breadth ......(1)

Also, Perimeter of blackboard is 22 feet.

That is, Perimeter of rectangle =  22 feet

We know, Perimeter of rectangle = 2 (length + Breadth)

substitute, we get,

22 = 2 (length + Breadth)  

11 = (length + breadth)   ........(2)

Let length be l and breadth be b

Solving (1) and (2) ,

from (2)

b = 11 - l  ..(3)

put (3)  in (1) , we get,

28 = L (11 - L)

Multiply, we get,

Solving above quadratic equation using middle term split method, we get,

Solving, e get,

Using zero product property, we get,

 and

We get ,

 and

Thus, length can be 4ft or 7 ft

Substitute, L in (3) , we get,

b = 11 - 4 = 7 ft

b = 11 - 7 = 4 ft

Thus, Dimension of board is 4 ft by 7 ft.

Option (c) is correct. hope it helped <3

5 0
4 years ago
Read 2 more answers
Mr. Howard is a student teacher at the local junior high. His first‐period class of 40 students averaged 96% on a recent test. H
kodGreya [7K]

Answer:

The combined average is 94%

Step-by-step explanation:

for first period, number of students =40

average =96%

for second period, no of students =20

average =90%

but average = \frac{sum of scores}{no of students}

let S_1 =sum of students for the first period

    S_2 =sum of students for the second period

for first period;

\frac{S_{1} }{40} =96%

S_{1}= 96*40=3840

for second period,

\frac{S_{2} }{20} =90%

S_{1}= 90*20=1800

therefore the combined average = \frac{S_1+S_2}{40+20}

that is \frac{3840+1800}{40+20} = 94%

so combined average is 94%

3 0
3 years ago
Read 2 more answers
7. What is the solution to the proportion below?
belka [17]
\frac{2y-9}{6} = \frac{y}{4}

Cross multiplying, we get:

4(2y-9) = 6y \\  \\ &#10;8y-36=6y \\  \\ &#10;8y-6y=36 \\  \\ &#10;2y=36 \\  \\ &#10;y=18

Thus the value of y for given proportion is 18.
3 0
3 years ago
If you are traveling 50 km per hour. How long would it take you to go 725 km
Shtirlitz [24]

Answer:

725/50= 14.5

14.5 hours is your answer

i think

6 0
4 years ago
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