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borishaifa [10]

2 years ago

9

laura compro un microondas por 216.750 y una lavadora 910.350 si le rebajaron 43.350 en la compra y el resto la paga en 15 plazo

s ¿cuanto paga en cada plazo?

1 answer:

Alecsey [184]2 years ago

7 0

RESPUESTA: Paga $72.250 en cada plazo.

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What is the value of x in the expression 2(6x + 4) - 6 + 2x = 3(4x + 3) + 1

irina [24]

Answer:

b.

Step-by-step explanation:

6 0

3 years ago

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The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

Maru [420]

Answer:

0.077994

Step-by-step explanation:

Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.

$H_0: Mean = 30\\H_a: Mean >30$

(Right tailed test)

Sample size = $n=250$

Sample mean = 30.45

Mean difference = $30.45-30=0.45\\$

Sample std dev s = 5

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Since population std deviation is not know we use t test

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4 0

3 years ago

Can someone help with #3 and show your work !!

ioda

If s represents the number of songs Kim downloads, her expenses for a month must satisfy the inequality
5.00 + 0.58·s ≤ 13.00

To solve this, subtract 5.00 to get the s-term by itself, then divide by the coefficient of s.
0.58·s ≤ 8.00
s ≤ 8.00/0.58 ≈ 13.79
The number of songs must be an integer, so we conclude Kim can download 13 songs, but not 14 songs.

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3 years ago

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Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha

kykrilka [37]

Answer:

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Step-by-step explanation:

Given that our random variable $X$ follows a Poisson distribution $P(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda$

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#since

$4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda$

The mean and variance of the Poisson distributed random variable is equal to $\lambda$ :

$\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75$

#By property variance:

$\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125$

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4 0

3 years ago

Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 244 meters

MissTica

We know that

[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x

Area=x*y-------> x*(122-x)----> 122x-x²

find the derivative function and equals to zero

122-2x=0-----> 122=2x----------> x=61 m
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<span>the maximum area is given by a square
</span>
the answer is
is a square of side 61 m

6 0

3 years ago