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iragen [17]
2 years ago
15

Which equation is related to √x+10-1=x ? The square root is over the x+10

Mathematics
1 answer:
Sergio [31]2 years ago
3 0

Answer:

  (b)  x + 10 = x^2 + 2x + 1

Step-by-step explanation:

The equation can be transformed to one without the radical by isolating the radical and squaring both sides.

__

  \sqrt{x+10}-1=x\qquad\text{given}\\\\\sqrt{x+10}=x+1\qquad\text{add 1 to both sides}\\\\x+10=(x+1)^2\qquad\text{square both sides}\\\\\boxed{x+10=x^2+2x+1}\qquad\text{eliminate parentheses}

_____

<em>Additional comment</em>

In typeset formulas, radicals, fraction bars, and superscript formatting serve to group expressions. In plain text, the only available grouping symbol is parentheses.

  \sqrt{x+1}}\ \Rightarrow √(x+1)

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<h3>Divisibility of Numbers</h3>

We are given the digit as 14, 213, 1__2.

Now, we see that the first of the last two digits is blank and for the give digit 14, 213, 1__2 to be divisible by 4 then the last two digits must be divisible by 4.

Now, since the last 2 digits must be divisible by 4, then it means any singe digit odd number we put in the blank space will yield a combined digit that is divisible by 4. Let us check them;

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Step-by-step explanation:

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