Answer:
t= -1.33 recurring and -2
Step-by-step explanation:
3t²+4t+8=-6t
3t²+4t+6t+8
3t²+10t+8
This is a quadratic equation, it can be solved by using either factorisation, completing the square method or formulae method. For the purpose of this question, I would be using the formulae method.
-b±√(b²-4ac)/2a
Where a=3, b= 10 and c=8
-10±√(10²-4(3)(8))/2(3)
-10±√(100-96)/6
(-10±√4)/6
(-10±2)/6
-10+2/6 or -10-2/6
-8/6 or -12/6
-1.3333 recurring or -2
Answer:
3380yd
Step-by-step explanation:
65x13x4
Answer:
Third Option
Step-by-step explanation:
We know that the function 
is defined as 
. Since the denominator is 
then we know that 
when 
We also know that the division by 0 is not defined. Therefore, the limit of 
when "x" tends to 
is infinite.
The function 
is the inverse of
By definition, if we have a function f(x), its domain will be equal to the range of its inverse function 
. If 
, then 
This also happens for the function
If when 
then when 
Then, the answer is:
Answer:
The zeroes are 3 and -2...if u need explanation I am open but seem in a hurry
