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2 years ago

Fraces bonitas para decirle a tu nv? minimo 6

Mathematics

2 answers:

earnstyle [38]2 years ago

8 0

Answer:

it's. is now the MA plz I miss you

Marina CMI [18]2 years ago

7 0

si pudiera escoger entre vivir eternamente y vivir dos veces

yo escogeria vivir dos veces porque vivir una vida eterna sin ti a mi lado seria el mayor sufrimiento, ahora vivir dos veces me dejaria tranquilo porque despues del final de mi vida podria volver a encontrarme contigo y vivir todos los momentos bellos una vez mas y eso seria un sueño volviendose realidad

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A pecan pie is being served for dessert. One piece of pie has an arc length of 7.85 in. It has been cut into 8 equal pieces. Wha

pishuonlain [190]

Answer: 10 inches.

Step-by-step explanation:

Since the pecan pie is a circle, you can use this formula:

$arc\ length=r\theta$

Where "r" is the radius and $\theta$ is the central angle of the arc in radians.

If the pecan pie has been cut into 8 equal pieces then the central angle is:

$\theta=\frac{2\pi}{8}\\\\\theta={\frac{\pi}{4}$

Now you know the arc length and the central angle, then, you can solve for "r" from $arc\ length=r\theta$ :

$\frac{arc\ length}{\theta} =r$

Substituting values, you get that the radius of the pecan pie rounded to the nearest whole number is:

$r=\frac{7.85in}{\frac{\pi}{4}}\\\\r=10in$

8 0

3 years ago

The aspect ratio of a TV screen is a ratio of the screen's width to the screen's height. Suppose that Noel recycles an old TV sc

Paul [167]

If the diagonal is 32 than you will us

A^2 + b^2 = c^2

We will use the aspect ratio to find a common variable

4A = 3B

a = (3/4)B now plug it in

((3/4)B)^2 + b^2 = 32 (This is because c is the diagonal)

Now solve for B

B turns out to be 25.577 inches

Plug B in

A = (3/4)(25.577)

A = 19.18

Now add up ther perimeter A + A + B + B

19.18 + 19.18 + 25.577 + 25.577

89.6 inches

8 0

3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

2 years ago

Jake and Erica were solving a system of equations. They both noticed that the two lines had the same slope. Jake said that becau

cluponka [151]

The correct answer is option A. Erica is correct in saying that the two lines are not necessarily the same and we should also look at the y-intercepts before determining how many solutions there were. Two lines with equal slopes could be the same line, but only if they have the same y-intercept.

3 0

3 years ago

Read 2 more answers

The following data values represent a population. What is the variance of the values? 7, 5, 11, 1, 11

MaRussiya [10]

The mean is 35/5=7

The variance is the average of the sum of squared differences of each element from the mean:

v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5

v=(0+4+16+36+16)/5

v=14.4

3 0

3 years ago

Read 2 more answers