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djverab [1.8K]
2 years ago
12

F(x-3)=f(x)-f(3)Prove:f(0)=0​

Mathematics
1 answer:
Sergio039 [100]2 years ago
8 0

Step-by-step explanation:

Let x=3.

So, f(3-3)=f(3)-f(3), and thus f(0)=0.

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I need help it has to be correct
Bess [88]

Answer:

cosine = adjacent / hypotenuse

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JL = cosine 62º * 17

JL = .47 * 17

JL = 7.99

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Step-by-step explanation:

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3 years ago
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

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2 years ago
What factors does Jenna need to model for the sides?
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I don’t see a picture or anything? Can you explain more I don’t know the sides
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3 years ago
Help me solve these two questions please!
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They are simple linear equations with one unknown, lets tackle them, one step at the time solving for the unknown:
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that is the solution.

3(6 - x) - 4 = 5x + 2(7x + 3)
18 - 3x - 4 = 5x + 14x + 6
14 - 3x = 19x + 6
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8 = 22x
x = 8/22 = 4/11
5 0
3 years ago
Does anyone know this?
monitta
The answer should be 101.
8 0
3 years ago
Read 2 more answers
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