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earnstyle [38]
2 years ago
11

Find the domain of the function y = 3 tan(2/3x)

Mathematics
1 answer:
Damm [24]2 years ago
5 0

Answer:

{x∈R | \frac{2x}{3\pi } +\frac{1}{2}, x∉Z}

Step-by-step explanation:

Given the function y=3tan(2/3x)

We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers

Also, the roots of y=3tan(2/3x) is 3\pi n/2 where n is an integer

Note that the domain of the function cannot be within 3\pi n/2

Therefore, {x∈R | \frac{2x}{3\pi } +\frac{1}{2}, x∉Z}

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In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known
mote1985 [20]

Answer:

  • arc BF = 76°
  • ∠M = 31°
  • ∠BGE = 121°
  • ∠MFB = 111°

Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

  ∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

  arc BF = 2∠FBM = 2(38°)

  arc BF = 76°

__

(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

  ∠M = (1/2)(138° -76°) = 62°/2

  ∠M = 31°

__

(c) arc FC is the supplement to arc BF, so has measure ...

  arc FC = 180° -arc BF = 180° -76° = 104°

∠BGE is half the sum of arcs BE and FC, so is ...

  ∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

  ∠BGE = 121°

__

(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

  ∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

  ∠MFB = 111°

3 0
4 years ago
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