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Katyanochek1 [597]
3 years ago
14

How do you make -11 into a decimal

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Answer:

-11.00

Step-by-step explanation:

Law Incorporation [45]3 years ago
3 0

Answer:

0.11

Step-by-step explanation:

because it is below zero the number goes behind the decimal.

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My index finger is 3.2in long... so in cm is it 8.128cm?
kiruha [24]
Yes that is correct..
8 0
3 years ago
Read 2 more answers
4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
Solve the system of linear equations below. 4x - 3y = 17 5x + 4y = 60
LenaWriter [7]
4x-3y=17......(1)
5x+4y=60......(2)

Multiply equation (1) by 4 and equation (2) by 3:-

16x - 12y = 68
15x + 12y = 180

Adding these 2 equations:_

31x = 248
x = 248/31 = 8

Now substitute x = 8 in equation (1):-

4(8) - 3y = 17
32-3y = 17
-3y = -15
y = -15/-3 = 5

So solution is x=8,y=5
5 0
3 years ago
Somebody please help​
iren [92.7K]

Answer:

Yes, No, No, No

Step-by-step explanation:

To decide whether the point lies on the circle, what you need to do it simply substituting the x and y values into the equation and check if it add up to be 25

(-5)² + 0² = 25, = RHS  [Yes]

1² + (√7)² = 8, ≠ RHS [No]

(√21)² + (-3)² = 30, ≠RHS [No]

0² + 7² = 49, ≠RHS [No]

5 0
3 years ago
Plssss helppp me plsss
adelina 88 [10]
6 I think but maybe 1
4 0
3 years ago
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