If there are no gaps you can get 9 pieces. Nut because 1/8" gap you can only get 8 pieces.
Answer:
b. 44°
Step-by-step explanation:
Reference angle = x
Hypotenuse = 21
Adjacent = 15
Apply trigonometric function CAH:
x = 44.4153086° ≈ 44° (nearest degree)
<span>Constraints (in slope-intercept form)
x≥0,
y≥0,
y≤1/3x+3,
y</span>≤ 5 - x
The vertices are the points of intersection between the constraints, or the outer bounds of the area that agrees with the constraints.
We know that x≥0 and y≥0, so there is one vertex at (0,0)
We find the other vertex on the y-axis, plug in 0 for x in the function:
y <span>≤ 1/3x+3
y </span><span>≤1/3(0)+3
y = 3.
There is another vertex at (0,3)
Find where the 2 inequalities intersect by setting them equal to each other
(1/3x+3) = 5-x Simplify Simplify Simplify
x = 3/2
Plugging in 3/2 into y = 5-x: 10/2 - 3/2 = 7/2
y=7/2
There is another vertex at (3/2, 7/2)
There is a final vertex where the line y=5-x crosses the x axis:
0 = 5 -x , x = 5
The final vertex is at point (5, 0)
Therefore, the vertices are:
(0,0), (0,3), (3/2, 7/2), (5, 0)
We want to maximize C = 6x - 4y.
Of all the vertices, we want the one with the largest x and smallest y. We might have to plug in a few to see which gives the greatest C value, but in this case, it's not necessary.
The point (5,0) has the largest x value of all vertices and lowest y value.
Maximum of the function:
C = 6(5) - 4(0)
C = 30</span>
Answer:
your answer is a i think sorry if im wrong
Step-by-step explanation:
Answer:
8 portraits are going to be used in the display.
Step-by-step explanation:
This problem can be solved as a rule of three problem.
Each yd has 36 inches.
The display is to span a total width of 10 yd. So it is a total width of 360 inches.
Each portrait has a width of 45 in. How many portraits can there be?
1 portrait - 45 in
x portraits - 360 in
8 portraits are going to be used in the display.
