Question

What is the distance between the points (2, 1) and (14, 6) on a coordinate plane?

Answer 1

Answer:

d = 13 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, 1 ) and (x₂, y₂ ) = (14, 6 )

d = $\sqrt{(14-2)^2+(6-1)^2}$

   = $\sqrt{12^2+5^2}$

   = $\sqrt{144+25}$

   = $\sqrt{169}$

   = 13

Answer 2

Answer:

On a coordinate plane the distance is 13 units between the two points.

Step-by-step explanation:

Given :

• (2, 1) and (14, 6)

Find the Distance

Solution:

• Applying Distance formulae,

$\rm \: D= \sqrt{(x_2 -x_1) {}^{2} +x_2 - x_1) {}^{2} }$

• $(y_2,y_1) = (6,1)$
• $(x_2,x_1) = (14,2)$

Solving,

• $D = \sqrt{(14 - 2) { }^{2} + (6 - 1 ){}^{2} }$
• $D= \sqrt{12 {}^{2} + 5 {}^{2} }$
• $D = \sqrt{144 + 25}$
• $D = \sqrt{169}$
• $D = \sqrt{13 \times 13}$
• $D= 13$

So distance is 13.